Question

Помогите решить
5x²-7 1/6 x+2 1/2 =0;

Answer 1

$5x^{2} -7\dfrac{1}{6} x+2\dfrac{1}{2}=0 \\\\5x^{2}-\dfrac{43}{6}x+\dfrac{5}{2} =0\\\\5x^{2}\cdot6-\dfrac{43}{6}x\cdot6+\dfrac{5}{2}\cdot6 =0\\\\30x^{2}-43x+15=0\\\\D=(-43)^{2}-4\cdot30\cdot15=1849-1800=49=7^{2}\\\\x_{1}=\dfrac{43-7}{60}=0,6\\\\x_{2}=\dfrac{43+7}{60} =\dfrac{5}{6} \\\\Otvet:\boxed{0,6 \ ; \ \dfrac{5}{6}}$