Question

решите уравнение x2 + 4x + 1 = 0​

Answer 1

$x^{2}+4x+1=0\\\\D=4^{2}-4\cdot1=16-4=12=(2\sqrt{3} )^{2}\\\\x_{1} =\dfrac{-4-2\sqrt{3}}{2}=-2-\sqrt{3}=-(\sqrt{3}+2) \\\\x_{2} =\frac{-4+2\sqrt{3} }{2}=\sqrt{3}-2\\\\Otvet:\boxed{-(\sqrt{3}+2) \ ; \ \sqrt{3} -2}$