Question

$arccos \frac{ \sqrt{2} }{2} + arctg( - \sqrt{3} )$
Обчислить:​

Answer 1

$arccos\frac{\sqrt{2} }{2}+arctg(-\sqrt{3})=\frac{\pi }{4}-arctg(\sqrt{3})= \frac{\pi }{4}-\frac{\pi }{3}=-\frac{\pi }{12}$