Question

помогите пожалуйста срочно!!! ответы с photomath-минус баллы

Answer 1

$\left\{\begin{array}{l}3^{x+y}=27 \\5^{(x-y)^{2}-1 }=1 \end{array}\right \\\\\\ \left\{\begin{array}{l}3^{x+y}=3^{3} \\5^{(x-y)^{2}-1 }=5^{0} \end{array}\right\\\\\\\left\{\begin{array}{l}x+y=3\\(x-y)^{2}-1=0 \end{array}\right\\\\\\\left\{\begin{array}{l}x+y=3\\(x-y)^{2}=1 \end{array}\right\\\\\\1)\\+\left\{\begin{array}{l}x+y=3\\x-y=-1 \end{array}\right\\--------\\2x=2\\\\x_{1} =1\\\\y_{1} =3-x=3-1=2\\\\\\2)\\+\left\{\begin{array}{l}x+y=3\\x-y=1 \end{array}\right\\--------$

$2x=4\\\\x_{2} =2\\\\y_{2}=3-x=3-2=1\\\\Otvet:\boxed{(1 \ ; \ 2) \ , \ (2 \ ; \ 1)}$