Question

$\frac{5a^{2} -5}{3a^{2} } :\frac{(a+1)^{2} }{5a^{2} }$

Answer 1

Ответ:

$\frac{5a^{2} -5}{3a^{2} } :\frac{(a+1)^{2} }{5a^{2} } = \frac{5(a - 1)(a + 1)}{3a {}^{2} } \times \frac{5a {}^{2} }{(a + 1) {}^{2} } = \frac{5a - 5}{3 } \times \frac{5}{a + 1} = \frac{25a - 25}{3a + 3}$