Question

$\frac{64-x^{2} }{28y^{2} } :\frac{x+8}{14y^{4} }$

Answer 1

Ответ:

$\frac{64-x^{2} }{28y^{2} } :\frac{x+8}{14y^{4} } = \frac{(8 - x)(8 + x)}{28y {}^{2} } \times \frac{14y {}^{4} }{x + 8} = \frac{8 - x}{2} \times y {}^{2} = \frac{8y {}^{2} - xy {}^{2} }{2}$