Question

find the slope of a line 2x-3y+1=0

Answer 1

Ответ:

33.69°

Объяснение:

normal equation of a straight line is    y=kx+b

k - is slope of a straight line

2x-3y+1=0

3y=2x+1

y=(2x+1) : 3

y=$\frac{2}{3} x +\frac{1}{3}$

$k=\frac{2}{3}$

if A is angle of inclination of a straight line then

k=tg(A)

tg(A) = $\frac{2}{3}$

A=33.6900675259798°