Question

Спростити вираз (фото)

Answer 1

$\dfrac{96}{b^{2}+2b } \cdot\dfrac{b+2}{2b-8}-\dfrac{3b}{b-4}=\dfrac{96}{b(b+2)}\cdot \dfrac{b+2}{2(b-4)}-\dfrac{3b}{b-4}=\\\\=\dfrac{48}{b(b-4)}-\dfrac{3b}{b-4}=\dfrac{48-3b^{2} }{b(b-4)}=\dfrac{3(16-b^{2} )}{b(b-4)} =\dfrac{3(4-b)(4+b)}{b(b-4)}=\\\\=\boxed{-\frac{3(b+4)}{b}}$

Answer 2

Ответ:

В решении.

Объяснение:

Упростить:

96/(b² + 2b) * (b + 2)/(2b - 8) - 3b/(b - 4) =

= 96/b(b + 2) * (b + 2)/2(b - 4) - 3b/(b - 4) =

= 48/b(b - 4) - 3b/(b - 4) =

= (48 - 3b²)/b(b - 4) =

= -3(b² - 16)/b(b - 4) =

= -3(b - 4)(b + 4)/b(b - 4) =

= -3(b + 4)/b.