Предмет: Математика, автор: Bobur009

Площадь прямоугольника равна 360 см2, основание равно 24 см. Найдите
площадь квадрата, периметр которого в три раза больше периметра
прямоугольника.
помогите пж у меня завтра экзамен 31 мая пж

ruslana770614: https://znanija.com/task/44025995
Bobur009: Ооооо чел спасибо огромное
ruslana770614: Не за что

Ответы

Автор ответа: Umka477
1

Пошаговое объяснение:

S=ab=360 cm²→ b=S/a=360/24=15

P(прямоугольника)=2(a+b)=2(15+24)=2•39=78→

P(квадрата) =3•Р(прямоугольника)=3•78=234

Р(квадрата) =4а→а=Р/4= 58.5

S=а²=58.5²=3422.25см²

Bobur009: Спасибо но девочка в комментах которая дала ссылку мне она молодец и решила но просто хотела помочь мне без балов но всеравно чел спасибо я поставлю 5 звёзд и спасибо!
Umka477: Я как бы тоже не за баллы.......
Bobur009: Ну ок :)
Bobur009: У меня завтра экз надеюсь справлюсь
ruslana770614: Umka477 тоже сам решил, он, наверное, даже и не смотрел ссылку. А Вам удачи на экзамене.
Bobur009: Спасибо вам тоже если вы студентка
Umka477: Я увидела ссылку уже после того, как опубликовала ответ
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