Question

Помогите решить 30 баллов срочно

Answer 1

Ответ:

а

$y '= 7 {x}^{6} - (3 {x}^{ \frac{7}{4} } ) '+ ( {x}^{ - 5} ) '- 0 = \\ = 7 {x}^{6} - 3 \times \frac{7}{4} {x}^{ \frac{3}{4} } - 5 {x}^{ - 6} = \\ = 7 {x}^{6} - \frac{21}{4} \sqrt[4]{ {x}^{3} } - \frac{5}{ {x}^{6} }$

б

$y' = ( {e}^{x} )'arctgx + (arctgx)' \times e {}^{x} = \\ = {e}^{x} arctgx + \frac{ {e}^{x} }{1 + {x}^{2} } = {e}^{x} (arctgx + \frac{1}{x {}^{2} + 1} )$

в

$y' = \frac{( {4}^{x})' \sin(x) - ( \sin(x)) ' \times {4}^{x} }{ \sin {}^{2} (x) } = \\ = \frac{ ln(4) \times {4}^{x} \sin(x) - {4}^{x} \cos(x) }{ \sin {}^{2} (x) } = \frac{ {4}^{x} ( ln(4) \sin(x) - \cos(x)) }{ \sin {}^{2} (x) }$