Question

помогите, пожалуйста

25x^2+10x+1/5x^2-9x-2

Answer 1

Объяснение:

▪︎1.

$25 {x}^{2} + 10x + 1 = 0 \\ d = 100 - 4 \times 25 \times 1 = 0 \\ x(1.2) = \frac{ - 10}{50} = - 0.2$

▪︎2.

$5 {x}^{2} - 9x - 2 = 0 \\ d = 81 + 4 \times 5 \times 2 = 121 \\ x(1) = \frac{9 + \sqrt{121} }{10} = \frac{9 + 11}{10} = 2 \\ x(2) = \frac{9 - 11}{10} = - 0.2$

▪︎3.

$\\ \frac{25 {x}^{2} + 10x + 1}{5 {x}^{2} - 9x - 2 } = \frac{a(x - x1)(x - x2)}{a(x - x1)(x - x2)} = \frac{25(x + 0.2) ^{2} }{5(x + 0.2)(x - 2)} = \frac{5x + 5}{x - 2}$