Question

ПОМОГИТЕ ПОЖАЛУЙСТА!!!!​

Answer 1

Ответ:

$2)\ \ sinx=-\dfrac{\sqrt2}{2}\\\\x=(-1)^{n}\cdot \Big(-\dfrac{\pi}{4}\Big)+\pi n\ ,\ \ \ x=(-1)^{n+1}\cdot \dfrac{\pi}{4}+\pi n\ ,\ n\in Z\\\\\\3)\ \ tgx=-2\\\\x=arctg(-2)+\pi n\ \ ,\ \ \ x=-arctg2+\pi n\ ,\ n\in Z\\\\\\4)\ \ ctgx=-\dfrac{\sqrt3}{2}\\\\x=arcctg\Big(-\dfrac{\sqrt3}{2}\Big)+\pi n\ \ ,\ \ \ x=\pi -arcctg\dfrac{\sqrt3}{2}+\pi n\ ,\ n\in Z$

$5)\ \ sin\Big(2x+\dfrac{\pi}{6}\Big)=-\dfrac{\sqrt3}{2}\\\\2x+\dfrac{\pi}{6}=(-1)^{n+1}\cdot \dfrac{\pi}{3}+\pi n\ \ ,\ \ \ 2x=-\dfrac{\pi }{6}+(-1)^{n+1}\cdot \dfrac{\pi}{3}+\pi n\ ,\ n\in Z\\\\x=-\dfrac{\pi}{12}+(-1)^{n+1}\cdot \dfrac{\pi}{6}+\dfrac{\pi n}{2}\ ,\ n\in Z\\\\x=(-1)^{n+1}\cdot \dfrac{\pi}{6}-\dfrac{\pi }{12}+\dfrac{\pi n}{2}\ ,\ n\in Z$