Question

розв'яжіть систему х^2-у^2=16
х+у=8​

Answer 1

Ответ:

${x}^{2} - {y}^{2} = 16 \\ x + y = 8 \\ \\ x = 8 - y \\ \\ ( {8 - y})^{2} - {y}^{2} = 16 \\ 64 - 16y + {y}^{2} - {y}^{2} = 16 \\ 64 - 16y = 16 \\ - 16y = 16 - 64 \\ - 16y = - 48 \\ y = 3 \\ \\ x = 8 - 3 \\ x = 5$

(x;y) = (5;3)