Question

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$f(x) = \frac{1}{ \sin{}^{2} 4x }$
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Answer 1

Ответ:

$f(x)=\dfrac{1}{sin^24x}\ \ ,\ \ \ \ \boxed{\Big(\dfrac{1}{u}\Big)'=\dfrac{-u'}{u^2}\ }\\\\\\f'(x)=\dfrac{-2\, sin4x\cdot cos4x\cdot 4}{sin^44x}=-\dfrac{8\cdot cos4x}{sin^34x}$