Question

ПОМОГИТЕ СРОЧНО
Представьте трехчлен в виде произведения :​

Answer 1

$5x^2+10xy+5y^2=5(x^2+2xy+y^2)=5(x+y)^2\\\\ax^2-4ax+4a=a(x^2-4x+4)=a(x-2)^2\\\\x^3+2x^2+x=x(x^2+2x+1)=x(x+1)^2\\\\ax^2-2axy+ay^2=a(x^2-2xy+y^2)=a(x-y)^2$

Answer 2

Ответ:

$5x {}^{2} + 10xy + 5y {}^{2} = 5(x {}^{2} + 2xy + y {}^{2} ) = 5(x + y) {}^{2}$

$ax {}^{2} - 4ax + 4a = a(x {}^{2} - 4x + 4) = a(x - 2) {}^{2}$

$x {}^{3} + 2x {}^{2} + x = x(x {}^{2} + 2x + 1) = x(x + 1) {}^{2}$

$ax {}^{2} - 2axy + ay {}^{2} = a(x - y) {}^{2}$