Question

Эх...снова я обращаюсь к вам)

Answer 1

Пошаговое объяснение:

$\begin {cases}x + 5y - 7 = 0 \\ x - 3y = - 1 \: \: \: | \times ( - 1)\end {cases} = > \begin {cases}x + 5y = 7 \\ - x + 3y = - 1\end {cases} \\ 8y = 8 \\ y = 1 \\ x - 3 = - 1 \\ x = 2$

Ответ : (х ; у) = (2 ; 1)

$\begin {cases}x - 3y - 4 = 0 \\ 5x + 3y + 1 = 0\end {cases} = > \begin {cases}x - 3y = 4 \\ 5x + 3y = - 1\end {cases} \\ 6x = 3 \\ x = \frac{1}{2} \\ \frac{1}{2} - 3y = 4 \\ y = - \frac{7}{6}$

Ответ : (х ; у) = ( 1/2 ; - 7/6)

$\begin {cases}36x + 33y + 3 = 0 \: \: \: | \div ( - 3)\\ 12x - 13y + 25 = 0\end {cases} = > \begin {cases} - 12x - 11y = 1 \\ 12x - 13y = - 25\end {cases} \\ - 24y = - 24 \\ y = 1 \\ 12x - 13 = - 25 \\ x = - 1$

Ответ : (х ; у) = (-1 ; 1)

Answer 2

Ответ:

$\left \{ {{x+5y-7=0} \atop {x-3y=-1}} \right. \\\left \{ {{x+5y=7} \atop {x-3y=-1}} \right.\\8y=8\\y=1\\2+5=7\\x=2$

$\left \{ {{x-3y-4=0} \atop {5x+3y+1=0}} \right. \\\left \{ {{x-3y=4} \atop {5x+3y=-1}} \right. \\6x=3\\x=0.5\\0.5-(-3.5)=4\\y=-1\frac{1}{6}$

$\left \{ {{36x+33y+3=0} \atop {12x-13y+25=0}} \right. \\\left \{ {{36x+33y=-3} \atop {12x-13y=-25}} \right. \\\left \{ {{36x+33y=-3} \atop {36x-39y=-75}} \right.\\72y=72\\y=1\\-36+33+3=0\\\\x=-1$

Пошаговое объяснение: