Question

log0.3(−x+2)≤log0.3(2x−2)

Answer 1

Ответ:

$(1;1\frac{1}{3}]$

Пошаговое объяснение:

$log_{0,3}(-x+2)\leq log_{0,3}(2x-2)\\\\OD3:\\\left \{ {{-x+2>0} \atop {2x-2>0}} \right.=>\left \{ {{-x>-2} \atop {2x>2}} \right.=>\left \{ {{x<2} \atop {x>1}} \right.=>x\in(1;2)\\\\0<0,3<1\\-x+2\geq 2x-2\\-x-2x\geq -2-2\\-3x\geq -4\\x\leq 4/3\\x\leq 1\frac{1}{3}\\\\x\in(1;1\frac{1}{3}]$