Question

$\frac{2 - b}{2} + \frac{2b}{2 + b}$
$c - \frac{c^{2} }{c + 1}$
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Answer 1

$\frac{2 - b}{2} + \frac{2b}{2 + b} = \frac{(2 - b)(2 + b) + 2b}{2(2 + b)} = \frac{4 - {b}^{2} + 2b}{2(2 + b)}$

$c - \frac{ {c}^{2} }{c + 1} = \frac{c(c + 1) - {c}^{2} }{c + 1 } = \frac{ {c}^{2} + c - {c}^{2} }{c + 1} = \frac{c}{c + 1}$