Question

найдите производную функции ​

Answer 1

Объяснение:

$y' = \sqrt{x} ( - 2x + 1)$

$y' = \frac{d}{dx} ( \sqrt{x \times ( - 2x + 1))}$

$y' = \frac{d}{dx} ( \sqrt{ - 2x {}^{2} } + x)$

$y' = \frac{d}{d \: g} ( \sqrt{g) \times \frac{d}{dx} } ( - 2x {}^{2} + x)$

$y' = \frac{1}{2 \sqrt{g} } \times ( - 2 \times 2x + 1)$

$y' = \frac{1}{2 \sqrt{ - 2x {}^{2} + x } } \times ( - 2 \times 2x + 1)$

$y '= \frac{ - 4x + 1}{2 \sqrt{ - 2x {}^{2} } + x}$