Question

х^2(4-х)
--------------- ≤0
х^2-10х+25​

Answer 1

$\frac{ {x}^{2}(4 - x) }{ {x}^{2} - 10x + 25 } \leqslant 0$

$\frac{ {x}^{2} (4 - x)}{ {(x - 5)}^{2} } \leqslant 0$

Ответ: х∈(-∞;0]U[4;5)U(5;+∞)