Question

50 баллов срочно очень​

Answer 1

Ответ:

1.

$f'(x) = 3 {x}^{2} - 8x + 2$

2.

$f'(x) = 9 {x}^{2} + \frac{1}{4} \times 4 {x}^{3} - 4x + 5 = \\ = 9 {x}^{2} + {x}^{3} - 4x + 5$

3.

$f'(x) = ( \sqrt{x} (2 - 5x))' = (2 \sqrt{x} - 5x \sqrt{x} ) '= \\ = (2 {x}^{ \frac{1}{2} } - 5 {x}^{ \frac{3}{2} } ) '= 2 \times \frac{1}{2} {x}^{ - \frac{1}{2} } - 5 \times \frac{3}{2} {x}^{ \frac{1}{2} } = \\ = \frac{1}{ \sqrt{x} } - \frac{15}{2} \sqrt{x}$

4.

$f'(x) = \frac{( {x}^{2} - 8x)'(x + 2) - (x + 2)'( {x}^{2} - 8x)}{ {(x + 2)}^{2} } = \\ = \frac{(2x - 8)(x + 2) - 1 \times ( {x}^{2} - 8x)}{ {(x + 2)}^{2} } = \\ = \frac{2 {x}^{2} + 4x - 8x - 16 - {x}^{2} + 8x}{ {(x + 2)}^{2} } = \\ = \frac{ {x}^{2} + 4x - 16}{ {(x + 2)}^{2} }$