Question

решите уравнение решите уравнение​

Answer 1

$tg^{2}x-\sqrt{3}tgx=\sqrt{3}-tgx\\\\tg^{2}x-\sqrt{3}tgx+tgx-\sqrt{3}=0\\\\tg^{2}x +(1-\sqrt{3} )tgx-\sqrt{3} =0\\\\tgx=m\\\\m^{2}+(1-\sqrt{3} )m-\sqrt{3} =0\\\\D=(1-\sqrt{3})^{2}-4\cdot(-\sqrt{3})=1-2\sqrt{3} +3+4\sqrt{3}=4+2\sqrt{3} =(\sqrt{3}+1)^{2}\\\\m_{1}=\frac{-(1-\sqrt{3})-(\sqrt{3}+1) }{2}=\frac{-1+\sqrt{3}-\sqrt{3}-1}{2}=-1\\\\m_{2} =\frac{-(1-\sqrt{3})+\sqrt{3}+1}{2}=\frac{-1+\sqrt{3} +\sqrt{3}+1 }{2} =\sqrt{3}$

$1)tgx=-1 \ \Rightarrow \ \boxed {x=-\frac{\pi }{4}+\pi n,n\in Z}\\\\2)tgx=\sqrt{3} \ \Rightarrow \ \boxed{x=\frac{\pi }{3}+\pi n,n\in Z}$