Question

4. Решите систему неравенств:


{х²+7х+10>0
{4х+28>0

Answer 1

Ответ:

$\left\{\begin{array}{l}x^2+7x+10>0\\4x+28>0\end{array}\right\ \ \left\{\begin{array}{l}(x+5)(x+2)>0\\4x>-28\end{array}\right\ \ \left\{\begin{array}{l}x\in (-\infty ;-5)\cup (-2;+\infty )\\x>-7\end{array}\right\\\\\\Otvet:\ \ x\in (-7\ ;-5\ )\cup (-2\ ;+\infty \, )$