Question

Помогите с математикой прошу

Answer 1

А) (1-cos75⁰)/sin75⁰ = tg(75⁰/2) = tg37,5⁰

Б) sin36⁰/(1+cos36⁰) = tg(36⁰/2) = tg18⁰

В) √(1-cos62⁰)/(1+cos62⁰) = √(sin²(62/2)⁰/cos²(62/2)⁰) = √(tg²31⁰) = tg31⁰