Question

х²-4х-32=0 срочно пожалуйста​

Answer 1

Ответ:

$d = ( - 4) {}^{2} - 4 \times 1 \times ( - 32) = 16 + 128 = 144 = 12 \\ x1 = \frac{4 + 12}{2} = \frac{16}{2} = 8 \\ x2 = \frac{4 - 12}{2} = - \frac{8}{2} = - 4$

Answer 2

Ответ:

$x_{1} = 8\\x_{2} = -4$

Объяснение:

Дискриминант:

$x^{2} -4x-32 = 0\\D = 16 + 32*4 = 16 + 128 = 144\\x_{1} = \frac{4 + 12}{2} = 8\\x_{2} = \frac{4-12}{2} = -4$

Виет:

$x^{2} -4x-32 = 0\\\left \{ {{x_{1} x_{2}=-32} \atop {x_{1}+x_{2} =4}} \right. \\\left \{ {{x_{1} =8} \atop {x_{2} = -4}} \right.$