Question

Помогите пожалуйста

Answer 1

Ответ:

Объяснение:

2 . sin(π/3 + α) + sin(π/3 - α) = sinπ/3cosα + cosπ/3sinα + sinπ/3cosα - cosπ/3sinα =

= 2sinπ/3cosα = 2* √3/2 *cosα = √3 cosα = [ cosα = 1 ] = √3 * 1 = √ 3 .

В - дь : √ 3 .

3 . . . . = [ sin3β + ( sin5β + sinβ )] / [ cos3β + ( cos5β + cosβ )] =

= ( sin3β + 2sin3βcos2β )/( cos3β + 2cos3βcos2β ) =

= sin3β ( 1 + 2cos2β )/cos3β( 1 + 2cos2β ) = sin3β/cos3β = tg3β .

В - дь : tg3β .