Question

ПЖЖЖЖЖЖЖЖЖЖЖЖЖ срочно

Answer 1

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Answer 2

Ответ:

$\dfrac{2a}{a-4}-\dfrac{5a-2}{16-a^2}=\dfrac{2a}{a-4}-\dfrac{5a-2}{(4-a)(4+a)}=\dfrac{2a}{a-4}+\dfrac{5a-2}{(a-4)(a+4)}=\\\\\\=\dfrac{2a(a+4)+5a-2}{(a-4)(a+4)}=\dfrac{2a^2+8a+5a-2}{(a-4)(a+4)}=\dfrac{2a^2+13a-2}{(a-4)(a+4)}$