Question

$(2x - y = 3$
$(x2 + 3xy = 10$
​

Answer 1

Объяснение:

$\left \{ {{2x-y=3} \atop {x^2+3xy=10}} \right. \ \ \ \ \left \{ {{y=2x-3} \atop {x^2+3x*(2x-3)=10}} \right. \ \ \ \ \left \{ {{y=2x-3} \atop {x^2+6x^2-9x=10}} \right.\ \ \ \ \left \{ {{y=2x-3} \atop {7x^2-9x-10=0}} \right. \\7x^2-9x-10=0\\D=361\ \ \ \ \sqrt{D}=19\\x_1=-\frac{5}{7}\\y_1=2*(-\frac{5}{7})-3=-\frac{10}{7} -3=-1\frac{3}{7}-3=-4\frac{3}{7}.\\x_2=2\\y_2=2*2-3=4-3=1.$

Ответ: (-⁵/₇;-4³/₇),  (2;1).