Question

помогите пожалуйстааа​

Answer 1

$\frac{a {}^{2} + 2a + 1 }{b {}^{2} - 4} \times \frac{b + 2}{a + 1} - \frac{a}{b + 2} \\ 1) \frac{a {}^{2} + 2a + 1 }{b {}^{2} - 4} \times \frac{b + 2}{a + 1} = \frac{(a + 1) {}^{2} }{(b - 2)(b + 2)} \times \frac{b + 2}{a + 1} = \frac{a + 1}{b - 2} \\ 2) \frac{a + 1}{b - 2} - \frac{a}{b + 2} = \frac{(a + 1)(b + 2) - a(b - 2) }{(b - 2)(b + 2)} = \frac{ab + 2a + b + 2 - ab + 2a}{b {}^{2} - 4 } = \frac{4a + b + 2}{b {}^{2} - 4 }$

Answer 2

$\frac{a^2+2a+1}{b^2-4}$$*\frac{b+2}{a+1}$$-\frac{a}{b+2}$$=\frac{(a+1)^2}{(b-2)(b+2)}$$*\frac{b+2}{a+1}$$-\frac{a}{b+2}$$=\frac{a+1}{b-2}$$-\frac{a}{b+2}$=

=(b+2)(a+1)-a(b-2)=ab+2a+b+2-ab+2a=4a+b+2

P.s.: думаю, решение такое