Question

log5 (7x + 4) = l + log5 (2x – 1)

Answer 1

log5(7x+4)=1+log5(2x-1)         одз 2x-1>0    x>1/2
log5(7x+4)=log5 5+log5(2x-1)
log5(7x+4)=log5   5(2x-1)
7x+4=10x-5
-3x=-9
x=3