Question

решите систему способом подстановки {x-3y=8;{2x-y=6​

Answer 1

Ответ:

$\left\{\begin{array}{l}x-3y=8\\2x-y=6\end{array}\right\left\{\begin{array}{l}x=3y+8\\2\, (3y+8)-y=6\end{array}\right\left\{\begin{array}{l}x=3y+8\\6y+16-y=6\end{array}\right\\\\\\\left\{\begin{array}{l}x=3y+8\\5y=-10\end{array}\right\ \ \left\{\begin{array}{l}x=3\cdot (-2)+8\\y=-2\end{array}\right\ \ \left\{\begin{array}{l}x=2\\y=-2\end{array}\right\ \ \ Otvet:\ (2;-2)\ .$