Question

Разложите на множители Зху^2 - 4х + ху -12y^2 + 16-4у
СРОЧНОООООО!!!!!!!!!!!!!!!!!!!

Answer 1

$3xy {}^{2} - 4x + xy - 12y {}^{2} + 16 - 4y = x \times (3y {}^{2} - 4 + y) - 4(3y {}^{2} - 4 + y) = (3y {}^{2} - 4 + y) \times (x - 4) = (3y {}^{2} + y - 4) \times (x - 4) = (3y {}^{2} + 4y - 3y - 4) \times (x - 4) = (y \times (3y + 4) - (3y + 4)) \times (x - 4) = (3y + 4) \times (y - 1) \times (x - 4)$