Question

АЛГЕБРА 40 БАЛЛОВ....

Answer 1

Ответ:

$\sqrt{0.25 \times 1.6 \times 10 } = \sqrt{4} = 2$

$2 \sqrt{7 } + 13 \sqrt{7} - 10 \sqrt{7} = 5 \sqrt{7}$

Answer 2

Ответ:

$1)\ \ \sqrt{0,25\cdot 1,6\cdot 10}=\sqrt{0,5^2\cdot 16}=0,5\cdot \sqrt{4^2}=0,5\cdot 4=2\\\\\\2)\ \ 2\sqrt7+13\sqrt7-10\sqrt7=\sqrt}{7}\cdot (2+13-10)=5\sqrt7\\\\\\3)\ \ (\sqrt5+2)^2=25+4\sqrt5+4=29+4\sqrt5\\\\\\4)\ \ a=\sqrt3\ \ ,\ \ P=4\sqrt3-2\\\\P=2(a+b)\ \ ,\ \ 2(a+b)=4\sqrt3-2\ |:2\ \ \ ,\ \ \ a+b=2\sqrt3-1\ \ ,\\\\b=2\sqrt3-1-a\ \ ,\ \ \ b=2\sqrt3-1-\sqrt3=\sqrt3-1\\\\S=ab=\sqrt3\cdot (\sqrt3-1)=3-\sqrt3$