Question

1)(x+5)(x+5)-(x-1)(x-1)=48

Answer 1

$(x+5)(x+5)-(x-1)(x-1)=48$

$(x+5)^2-(x-1)^2=48$

$x^{2} +10x+25-( x^{2} -2x+1)=48$

$x^{2} +10x+25-x^{2} +2x-1=48$

$12x+24=48$

$12x=48-24$

$12x=24$

$x=24: 12$

$x=2$

Ответ:  $2$