Question

Помогите решить .........................................

Answer 1

Ответ:

Объяснение:

2) f(x) = 2 + 4x; M(-1; 1)

F(x) = 2x + 2x^2 + C

1 = 2(-1) + 2(-1)^2 + C = -2 + 2 + C

C = 1

F(x) = 2x + 2x^2 + 1

3) f(x) = cos(x - π/3); M(π/2; 1)

F(x) = sin(x - π/3) + C

1 = sin(π/2 - π/3) + C = sin(π/6) + C = 1/2 + C

C = 1 - 1/2 = 1/2

F(x) = sin(x - π/3) + 1/2

4) f(x) = sin(x - π/4); M(3π/2; 2)

F(x) = -cos(x - π/4) + C

2 = -cos(3π/2 - π/4) + C = -cos(5π/4) + C = -(-√2/2) + C = √2/2 + C

C = 2 - √2/2 = (4-√2)/2

F(x) = -cos(x - π/4) + (4-√2)/2