Question

СРОЧНО, ПОЖАЛУЙСТА, ПОМОГИТЕ С ЛОГАРИФМАМИ

Answer 1

log(x) y = z

x^z = y

x, y > 0 x ≠ 1

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log(4) x = -3

x = 4^(-3) = 1/4³ = 1/64

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log(1/7) x = 1

x = 1/7

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log(√5) x = 0

x = (√5)^0 = 1

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log(1/2) x = -3

x = (1/2)^(-3) = 2^3 = 8