Question

Помогите,пожалуйста,срочно!!!

Answer 1

$\left \{ {{\frac{6}{x-y}+\frac{8}{x+y}=-2|:2 } \atop {\frac{9}{x-y}+\frac{10}{x+y}=8}} \right.\\\\\left \{ {{\frac{3}{x-y}+\frac{4}{x+y}=-1}|*(-3) \atop {\frac{9}{x-y}+\frac{10}{x+y}=8}} \right.\\\\+\left \{ {{-\frac{9}{x-y}-\frac{12}{x+y}=3} \atop {\frac{9}{x-y}+\frac{10}{x+y}=8}} \right.\\--------\\-\frac{2}{x+y} =11\\\\x+y=-\frac{2}{11} \\\\\frac{3}{x-y}+\frac{4}{-\frac{2}{11} }=-1\\\\\frac{3}{x-y} -22=-1\\\\\frac{3}{x-y} =21\\\\x-y=\frac{3}{21}=\frac{1}{7}$

$+\left \{ {{x+y=-\frac{2}{11} } \atop {x-y=\frac{1}{7} }} \right. \\------\\2x=-\frac{2}{11}+\frac{1}{7}=-\frac{3}{77}\\\\x=-\frac{3}{154} \\\\y=x-\frac{1}{7} =-\frac{3}{154} -\frac{1}{7} =-\frac{3}{154}-\frac{22}{154} =-\frac{25}{154} \\\\Otvet:\boxed{(-\frac{3}{154} \ ; \ -\frac{25}{154})}$