Question

помогите пжл........​

Answer 1

$1)\frac{8x^{5}y^{2}}{16y^{4}x^{3}}=\frac{1}{2}x^{5-3} y^{2-4}=\frac{1}{2}x^{2}y^{-2}=\boxed{\frac{x^{2} }{2y^{2} }}\\\\\\2)\frac{x^{2}-16 }{4x+16}=\frac{(x+4)(x-4)}{4(x+4)}=\boxed{\frac{x-4}{4}}$

Answer 2

а)

$\frac{8 {x}^{5} {y}^{2} }{16 {y}^{4} {x}^{3} } = \frac{ {x}^{2} }{2 {y}^{2} }$

б)

$\frac{ {x}^{2} - 16 }{4x + 16} = \frac{(x - 4)(x + 4)}{4(x + 4)} = \frac{x - 4}{4}$