Question

Помогите ПЖПЖПЖПЖПЖ! Дам 50 баллов!

Answer 1

Ответ:

$\left\{\begin{array}{l}6x-9y=12\\5x+4y=17\end{array}\right\ \ \left\{\begin{array}{l}2x-3y=4\ |\cdot 5\\5x+4y=17\ |\cdot (-2)\end{array}\right\ \oplus \ \left\{\begin{array}{l}2x-3y=4\\-23y=-14\end{array}\right$

$\left\{\begin{array}{l}2x=4+3y\\y=\dfrac{14}{23}\end{array}\right\ \ \left\{\begin{array}{l}2x=4+3\cdot \dfrac{14}{23}\\y=\dfrac{14}{23}\end{array}\right\ \ \left\{\begin{array}{l}2x=\dfrac{134}{23}\\y=\dfrac{14}{23}\\\end{array}\right\ \ \left\{\begin{array}{l}x=\dfrac{67}{23}\\\ y=\dfrac{14}{23}\end{array}\right\\\\\\Otvet:\ \Big(\ \dfrac{67}{23}\ ;\ \dfrac{14}{23}\ \Big)\ .$