Question

корень3cosa-2cos(a-p/6)
Решите по братски

Answer 1

$sqrt{3} cos alpha -2cos( alpha - frac{pi}{6})=sqrt{3}cos alpha -2( frac{sqrt{3}}{2} cos alpha + frac{1}{2} sin alpha )=\ =sqrt{3}cos alpha -sqrt{3}cos alpha -sin sqrt{3}=-sin alpha$