Question

выполните действия
$\frac{2 - y}{y {2}^{ - } 9} + \frac{5 - 2y}{y - 3}$
срооочноо соооор 30 баллов​

Answer 1

2-y/y²-9 +5-2y/y-3 = 2-y+(y+3)(5-2y)/(y-3)(y+3) = 2-y+5y-2y²+15-6y/y²-9 = 17-2y-2y²/y²-9 = -2y²-2y+17/y²-9

Answer 2

$\frac{2-y}{y^{2}-9 } +\frac{5-2y}{y-3}=\frac{2-y}{(y-3)(y+3)} +\frac{5-2y}{y-3} =\frac{2-y+(5-2y)*(y+3)}{(y-3)(y+3)}=\\\\=\frac{2-y+5y+15-2y^{2}-6y }{(y-3)(y+3)} =\frac{-2y^{2}-2y+17 }{y}=-\frac{2y^{2}+2y-17 }{y^{2}-9 }$