Question

Решите систему неравенств.
{х^2-х-2<0
{5-2х<0

Answer 1

Ответ:

$\left\{\begin{array}{l}x^2-x-2<0\\5-2x<0\end{array}\right\ \ \left\{\begin{array}{l}(x+1)(x-2)<0\\2x>5\end{array}\right\ \ \left\{\begin{array}{l}x\in (-1\, ;\ 2\ )\\x\in (\ 2,5\ ;+\infty \, )\end{array}\right\\\\\\Otvet:\ x\in \varnothing \ .$