Question

${ \alpha }^{2} 4 \alpha + 1 = 0$
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Answer 1

Ответ:

$\alpha = -\frac{1}{\sqrt[3]{4} }$

Объяснение:

$\alpha ^{2} 4\alpha + 1 = 0\\4\alpha ^{3} = -1|:4\\\alpha ^{3} = -\frac{1}{4}$

$\alpha = \sqrt[3]{-\frac{1}{4} } = -\frac{1}{\sqrt[3]{4} }$