Question

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пожалуйста​

Answer 1

Ответ:

$(2 \sqrt{5x - 6} ) '= (2 {(5x - 6)}^{ \frac{1}{2} } ) '= \\ = 2 \times \frac{1}{2} {(5x - 6)}^{ - \frac{1}{2} } = \frac{1}{ \sqrt{5x - 6} }$

$( \frac{1}{ {x}^{5} } ) '= ( {x}^{ - 5}) '= - 5 {x}^{ - 6} = - \frac{5}{ {x}^{6} }$

$( - \frac{2}{ {x}^{ 3} } ) '= ( - 2 {x}^{ - 3} )' = - 2 \times ( - 3) \times {x}^{ - 4} = \frac{6}{ {x}^{4} }$

$( \frac{4}{(3x + 5) {}^{5} } )' = (4 {(3x + 5)}^{ - 5} )' = \\ = 4 \times ( - 5) \times {(3x + 5)}^{ - 6} \times (3x + 5) '= \\ = - \frac{20}{ {(3x + 5)}^{6} } \times 3 = - \frac{60}{ {(3x + 5)}^{6} }$

$( \frac{1}{ \sqrt[6]{ {x}^{5} } } )' = ( {x}^{ - \frac{5}{6} } )' = - \frac{5}{6} {x}^{ - \frac{11}{6} } = - \frac{5}{6x \sqrt[6]{ {x}^{5} } }$