Question

Срочно помогите пожалуйста.​

Answer 1

Ответ:

$a) \frac{x(x + 1) - x}{x + 1} = \frac{ {x}^{2} + x - x }{x + 1} = \frac{ {x}^{2} }{x + 1}$

б)

$\frac{(m + 2)(m + 4) - 4m}{4m(m + 4)} = \frac{ {m}^{2} + 4m + 2m + 8 - 4m}{4m(m + 4)} = \frac{ {m}^{2} + 4m + 8 }{4m(m + 4)} = \frac{ {m}^{2} + 4m + 8 }{ {4m}^{2} + 16}$

в)

$\frac{x(x - y) + y(x + y)}{(x - y)(x + y)} = \frac{ {x}^{2} - xy + xy + {y}^{2} }{(x - y)(x + y)} = \frac{ {x}^{2} + {y}^{2} }{(x - y)(x + y)} = \frac{ {x}^{2} + {y}^{2} }{ {x}^{2} - {y}^{2} } = \frac{(x + y)(x + y)}{(x - y)(x + y)} = \frac{x + y}{x - y}$

г)

$\frac{3x + y}{x(x + y)} - \frac{x + 3y}{y(y + x)} = \frac{y(3x + y) - x(x + 3y)}{xy(x + y)} = \frac{3xy + {y}^{2} - {x}^{2} - 3xy }{xy(x + y)} = \\ \frac{ {y}^{2} - {x}^{2} }{xy(x + y)} = \frac{(y - x)(y + x)}{xy(x + y)} = \frac{y - x}{xy}$