Question

решите 3 задание пжжжж​

Answer 1

Ответ:

-0,375

Объяснение:

$\frac{3x-9x^2}{x^2+6+9} : \frac{1-9x^2}{x^2-9} = \frac{3x(1-3x)}{(x+3)^2} : \frac{(1-3x)(1+3x)}{(x-3)(x+3)} = \frac{3x(1-3x)(x-3)(x+3)}{(x+3)(x+3)(1-3x)(1+3x)} = \frac{3x(x-3)}{(x+3)(1+3x)}$

Подставим x:

$\frac{3*1(1-3)}{(1+3)(1+3*1)} = \frac{3*(-2)}{4*4} = \frac{-6}{16}$ = -0,375