Question

срочно сьогодні сдавать​

Answer 1

${x}^{2} - 5x - 6 = (x - 6)(x + 1)\\ x_{1} + x_{2} = 5 \\ x_{1} \times x_{2} = - 6 \\ x_{1} = 6 \\ x_{2} = - 1$

по формуле :

$a{x}^{2} + bx + c = a(x - x_{1})(x - x_{2})$

$\frac{6 {x}^{2} - 5x + 1}{4x + 2} = \frac{2(x - \frac{1}{2} )(3x - 1)}{2(2x + 1)} = \frac{(x - \frac{1}{2}) (3x - 1)}{2x + 1} \\ 6x {}^{2} - 5x + 1 = 0 \\ d = ( - 5) {}^{2} - 4 \times 6 \times 1 = 25 - 24 = 1 \\ x_{1} = \frac{5 + 1}{12} = \frac{6}{12} = \frac{1}{2} \\ x_{2} = \frac{5 - 1}{12} = \frac{4}{12} = \frac{1}{3} \\ 6(x - \frac{1}{2} )(x - \frac{1}{3} ) = 2 \times 3 \times (x - \frac{1}{2} )(x - \frac{1}{3} ) =2 (x - \frac{1}{2} )(3x - 1)$

Answer 2

Объяснение:

2.

$x^2-5x-6=x^2-6x+x-6=x*(x-6)+(x-6)=(x-6)*(x+1).$

3.

$\frac{6x^2-5x+1}{4x-2}=\frac{6x^2-2x-3x+1}{2*(2x-1)}=\frac{2x*(3x-1)-(3x-1)}{2*(2x-1)}=\frac{(3x-1)*(2x-1)}{2*(2x-1)}=\\=\frac{3x-1}{2}=1,5x-0,5.$