Question

Выполните действия:
2-3y 5-2y
+
у2 -9 y-3​

Answer 1

Объяснение:

$\frac{2 - 3y}{ {y }^{2} - 9} + \frac{5 - 2y}{y - 3} = \frac{2 - 3y}{(y - 3)(y + 3)} + \frac{5 - 2y}{y - 3} = \frac{2 - 3y + (y + 3)(5 - 2y)}{(y - 3)(y + 3)} = \frac{2 - 3y + 5y - 2 {y}^{2} + 15 - 6y} { {y}^{2} - 9}^{ } = \frac{17 - 4y - 2 {y}^{2} }{ {y}^{2} - 9 } = \frac{ - 2 {y}^{2} - 4y + 17 }{ {y}^{2} - 9}$