Предмет: Геометрия, автор: Lolmsdyf

6. (1 бал) Відповідні сторони двох подібних чотирикутників відносяться як
2:5, а площа меншого з них дорівнює 24 см. Знайдіть площу більшого
чотирикутника.​

Ответы

Автор ответа: romaprihodko2006
1

S1=24 см^2

S1/S2=2/5

24/x=2/5

120=2x

x=60

Ответ: 60 см^2


Lolmsdyf: спасибо удачи
Lolmsdyf: тебе
abubabi: рома помоги мне с вопросом пжпжпж
romaprihodko2006: Сори. Наврядли смогу помочь.
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