Question

Срочно нужно пожалуйста ​

Answer 1

$\frac{y^{2}}{y+3}=\frac{y}{y+3} \\\\\frac{y^{2}}{y+3}-\frac{y}{y+3}=0\\\\\frac{y^{2}-y }{y+3}=0\\\\\frac{y(y-1)}{y+3}=0 \\\\y+3\neq0 \ \Rightarrow \ y\neq -3\\\\y(y-1)=0\\\\y_{1} =0\\\\y-1=0 \ \Rightarrow \ y_{2} =1\\\\\boxed{0 \ ; \ 1}$